Question

guyzz...

Plzz answer itt​

Answer 1

Answer:

Step-by-step explanation:

Here is your answer

Plz mark it brainiest as i need it

Answer 2

Answer:

Length of Wire is 112000 cm

Step-by-step explanation:

Given: OQ = QP, H = 10 cm   and OP = 20 cm

            ∠DOC = 60° and ∠DOP = 30°

            Radius of wire, r = $\frac{1}{12}\:cm$

To find: Length of wire, h

Let radius of frustum are $r_1=PD\,,\,r_2=QB$

In ΔPOD,

$tan\,30^{\circ}=\frac{PD}{OP}$

$\frac{1}{\sqrt{3}}=\frac{r_1}{20}$

$r_1=\frac{20}{\sqrt{3}}\:cm$

In ΔQOB,

$tan\,30^{\circ}=\frac{QB}{OQ}$

$\frac{1}{\sqrt{3}}=\frac{r_2}{10}$

$r_2=\frac{10}{\sqrt{3}}\:cm$

             

Volume of wire = volume of frustum

$\pi r^2h=\frac{1}{3}\pi H(r_1^2+r_2^2+r_1r_2)$

$(\frac{1}{12})^2h=\frac{1}{3}\times10((\frac{20}{\sqrt{3}})^2+(\frac{10}{\sqrt{3}})^2+(\frac{20}{\sqrt{3}})(\frac{10}{\sqrt{3}}))$

$\frac{1}{144}h=\frac{10}{3}(\frac{400}{3}+\frac{100}{3}+\frac{200}{3})$

$\frac{1}{144}h=\frac{10}{3}\times\frac{700}{3}$

$h=\frac{10}{3}\times\frac{700}{3}\times144$

$h=112000$

Therefore, Length of Wire is 112000 cm