Gyus plss tell why we can't take -x common. .....my solution is not coming correct and plss tell my mistake
Answers
Given : a/(x - a) + b/(x - b) = 2c/(x - c)
To find : Solve for x
Solution:
a/(x - a) + b/(x - b) = 2c/(x - c)
=> (a(x - b) + b(x - a) ) / (x - a)(x - b) = 2c/(x - c)
=> (ax + bx - 2ab) /(x² -ax -bx + ab) = 2c/(x - c)
=> (ax + bx - 2ab) (x - c) = 2c(x² -ax -bx + ab)
=> ax² + bx² -2abx -acx -bcx + 2abc = 2cx² -2acx -2bcx + 2abc
=> ax² + bx² - 2cx² -2abx + acx + bcx = 0
=> x( ax + bx - 2cx - 2ab + ac + bc) = 0
=> x = 0
or
ax + bx - 2cx - 2ab + ac + bc = 0
=> x(a + b - 2c) = 2ab - ac - bc
=> x = (2ab - ac - bc)/(a + b - 2c)
x = 0 or (2ab - ac - bc)/(a + b - 2c)
Learn more:
Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in
https://brainly.in/question/8168066
solve for x :(2x÷x-5)^2 +(10x÷ x-5 )-24=0
https://brainly.in/question/2356509