h=2tcos ○÷rp check it is dimensionally correct or not?
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ICSE Class 9
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Sum
Evaluate :
AA
AA
cos3A–2cos4Asin3A+2sin4A , when A = 15°
SOLUTION
(i) Given that A= 15°
AA
AA
cos3A–2cos4Asin3A+2sin4A=cos(3x15°)–2cos(4x15°)sin(3x15°)+2sin(4x15°)
=
cos45°–2cos60°sin45°+2sin60°
=
12–2(12)12+2(32)
=
12–112+3
=
1–21+6
=
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