Question

H.C.F. of 130 n 520 n 845

Answer 1

Given:

Three number 130, 520 and 845 .

To find:

HCF of 130 n 520 n 845

Solution:

1) HCF is the highest common factor to which all the given numbers are completely divisible.

2) We will find the HCF of the given numbers by the prime factorization.

• 130 = 2×5×13

• 520= 2×2×2×5×13

• 845=5×13×13

HCF[130,520, 845] = 5×13 =65

HCF of 130 n 520 n 845  is 65

Answer 2

Here is your answer

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