Question

h.c.f. of polynomials x2-y2 and x3-y3 is

Answer 1

answer is (x-y) .....

Answer 2

The factors of these polynomials :-

x²-y² = (x+y)(x-y)

and, x³-y³ = (x-y)(x²+xy+y²)

Thus, H.C.F. of these polynomials = (x-y)

Hope this helps.