H.C.F. of two numbers is 18 and their L.C.M is 270 . If one of those numbers is 90 then find the other 1)54 2)540 3)150 4)60
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lcm * hcf = product of the two numbers
270 * 18 = 4860
let the other number be x
∴ 4860 = 90 * x
x = 4860 ÷ 90
x = 54
the other no. is 54
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Hcf = 18 Lcm=270 We know that, Hcf*lcm=product of the numbers ie 18*270=90*x Therefore, x= 18*270/90 X = 54Attachments:
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