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Question - Calculate the cost of electricity for a house in which 6 bulbs of 60 watt each and 5 fans of 40 watt each are used for 10 hours a day for thirty days if the cost of each unit (kWh) is rs 1.05.

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Answer 1

Answer:

1 bulb = 60 watt .

so, 6 bulb = 60*6 ==> 360 watt

  1 fan = 40 watt ==> 5 fan ==> 40*5 ==> 200 watt

so, total watt ==> 360+200 ==> 560 watt

1 kw = 1000 watt

so, 560 watt ==> 560/1000 ==> 0.56 kw

each are used 10 hour in a day

  so, energy in a day = 0.56 × 10

     energy in a day = 5.6 kwh

energy in 30 days ==> 5.6×30 ==> 168 kwh

  rupees of 1 kwh = 1.05

  rupees of 168 kwh = 168×1.05 ==> 176.4

  answer = 176.4

Answer 2

Solution :- 6 bulbs of 60 watt each used for/hour consume.
6 × 60 = 360 Wh
When used for 10 hours consumption for each day
= 360 × 10 = 3600 Wh
5 fans of 40 watt each used for 1 hour consume
5 × 40 = 200 Wh
When used for 10 days hours consumption for each
= 200 × 10 = 2000 Wh
Total electricity consumed in 30 days

= 3600 × 30 + 2000 × 30
= ( 108000 + 60000 ) Wh
= 168000 Wh
= 168 kWh
Cost = 168 × 1.05
= Rs 176.40

Hope it helps u...