Question

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The annual incomes of A and B are in the ratio 3:4 and their annual expenditure are in the ratio 5:7.
If each saves ₹5,000 ; Find their annual incomes.....






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THOSE WHO KNOW THE ANSWER CAN ANSWER.....✔✅✔✅​

Answer 1

Answer:

→ 30,000 and 40,000 respectively.

Step-by-step explanation:

Let the ratio be in x and y .

Then, annual income = 3x and 4x .

And, their expenditure = 5y and 7y .

Now, A/Q,

→ 3x - 5y = 5,000 ...........(1).

And, 4x - 7y = 5,000 .........(2) .

By elimination method :

Multiplying equation (1) by 4 and equation (2) by 3 ,we get

→ 12x - 20y = 20,000 .........(3).

→ 12x - 21y = 15,000 ...........(4) .

On subtracting equation (3) and (4), we get

12x - 20y = 20,000 .

12x - 21y = 15,000 .

-..... +......... -

______________________

→ y = 5,000 .

Putting the value of 'y' in equation (1), we get

→ 3x - 5(5,000) = 5,000 .

→ 3x = 5,000 + 25,000 .

→ 3x = 30,000 .

→ x = 30,000/3 .

$\therefore$ x = 10,000 .

Then, the annual income :

→ Of A = 3x = 3 × 10,000 = ₹30,000 .

→ And, of B = 4x = 4 × 10,000 = ₹40,000 .

Hence, it is solved.

Answer 2

$\huge\bigstar\mathfrak\purple{\underline{\underline{SOLUTION}}}$

Let the income of A & B be 3x & 4x; &

the expenditure be 5y & 7y respectively.

A/q

3x -5y = 5000..........(1)

4x -7y= 5000...........(2)

On multiplying equation (1) by 4 & equation (2) by 3, we get

12x-20y= 20000.........(3)

12x-21y= 15000.........(4)

Subtracting equation (3) from (4)

12x-21y-12x+20y= 15000-20000

=) -y= -5000

=) y= 5000

On putting y= 5000 in equation (2),

=) 4x-7×5000= 5000

=) 4x- 35000= 5000

=) 4x=35000+5000

=) 4x= 40000

=) x= 10000

Thus, A's income, 3x= 3×10000= Rs.30000

&

B's income, 4x= 4×10000= Rs.40000

hope it helps ☺️