Question

H, gas and Fe30, are produced by the action of
27 g of steam on excess of iron. Further Ho
gas reacts with excess of N, to produce NH3.
Number of molecules of NH, formed will be
[No = Avogadro's constant]
(1) No
(2) 2No
(3)No/2
(4) 4No
​

Answer 1

Explanation:

H2 gas and Fe3O4 are produced by the action of 27g of ... Further H2 gas reacts with excess of N2 to produce NH3.

Answer 2

The number of molecules of ammonia formed will be $N_o$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of steam = 27 g

Molar mass of steam = 18 g/mol

Putting values in above equation, we get:

$\text{Moles of steam}=\frac{27g}{18g/mol}=1.5mol$

The chemical equation for the reaction of steam and iron metal follows the equation:

$3Fe+4H_2O\rightarrow Fe_3O_4+4H_2$

By Stoichiometry of the reaction:

4 moles of water (steam) produces 4 moles of hydrogen gas

So, 1.5 moles of steam will produce = $\frac{4}{4}\times 1.5=1.5mol$ of hydrogen gas

The chemical equation for the formation of ammonia follows:

$3H_2+N_2\rightarrow 2NH_3$

By Stoichiometry of the reaction:

3 moles of hydrogen gas produces 2 moles of ammonia

So, 1.5 moles of hydrogen gas will produce = $\frac{2}{3}\times 1.5=1mol$ of ammonia

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ or $N_o$ number of molecules

So, 1 mole of ammonia will contain = $(1\times N_o)=N_o$ number of molecules

Learn more about number of moles and mole concept:

https://brainly.com/question/10982990

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