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Answer 1

Let larger pipe rate be x hrs/job

Let smaller pipe rate be y hrs/job

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Equations:

x + y = 1/12

4x+9y = 1/2

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Modify to get:

24x + 24y = 2

24x + 54y = 3

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Subtract and solve for "y":

30y = 1

y = 1/30 job/hr (rate of the smaller diameter pipe)

Smaller pipe would take 30 hrs to fill the pool.

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Solve for "x"

x + (1/30) = 1/12

x = (1/12)-(1/30)

x = (18/(12*30)) = 1/20 job/hr

Larger pipe would take 20 hrs to fill the pool.