H of cone is 10 m circumfarance of its base
is 44 cm and the widhth is 2 m what will be the lenghth
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Let radius of the canonical tent is r and height is h
Now circumference of the base = 44
=> 2πr = 44
=> 2*(22/7)*r = 44
=> 44r/7 = 44
=> r/7 = 1
=> r = 7
Given h = 24
Now, CSA of tent = 2πrh
= 2 *(22/7)*7*24
= 1056
=> are of the canvas = 1056
=> length * breadth = 1056
Given, breadth = 2
So, Length = 1056/2
=> Length = 528 m
Now circumference of the base = 44
=> 2πr = 44
=> 2*(22/7)*r = 44
=> 44r/7 = 44
=> r/7 = 1
=> r = 7
Given h = 24
Now, CSA of tent = 2πrh
= 2 *(22/7)*7*24
= 1056
=> are of the canvas = 1056
=> length * breadth = 1056
Given, breadth = 2
So, Length = 1056/2
=> Length = 528 m
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