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Two vectors are given by —2i + 3 + 3k and 5i + 3j – 2k. If 3 à +27 - = = 0 then third vector é is
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Answer:
Given
a
=−2
i
^
+
j
^
−3
k
^
b
=−5
i
^
+3
j
^
−2k
as per question 3
a
+2
b
−
c
=0
−6
i
^
+3
j
^
−9
k
^
−10
i
^
+6
j
^
−4
k
^
−
c
=0
vecc=−16
i
^
+9
j
^
−13
k
^
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