∆H° for the reaction CH4 +2O2=CO2 +2H2O is - 890KJ, calculate ∆H° for the reaction CO2 +2H2O=CH4 +2O2
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Answer:
Calculate the enthalpy change for the following reaction:
CH
4
(g)+2O
2
(g)⟶CO
2
(g)+2H
2
O(l)
Given, enthalpies of formation of CH
4
,CO
2
and H
2
O are 74.8 kJmol
−1
,−393.5 kJmol
−1
,−286 kJmol
−1
respectively.
MEDIUM
ANSWER
ΔH
o
=ΔH
f(products)
o
−ΔH
f(reactants)
o
=[ΔH
(CO
2
)
o
+ΔH
(H
2
O)
o
]−[ΔH
(CH
4
)
o
+2ΔH
(O
2
)
o
]
=[−393.5+2×(−286.2)]−[−74.8+2×0]=−890.7kJ
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