Question

H2 gas and Fe3O4 produced by the action of 27 gram of steam on excess of iron. Further the H2 gas reacts with excess of N2 to produce NH3 number of molecules of NH3 formed will be?
1.Avagadro number
2. 2× Avagadro no.
3.Avagadro no. /2
4. 4×avagadro no. ​

Answer 1

Explanation:

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Answer 2

The correct answer is option (1) Avogadro Number.

The correct answer is option (1) Avogadro Number. GIVEN

H₂ gas and Fe₃O₄ produced by the action of 27 gram of steam on excess of iron. Further the H₂ gas reacts with excess of N₂ to produce NH₃.

TO FIND

Number of molecules of NH₃ formed.

SOLUTION

We can simply solve the above problem as follows;

The reaction between Iron and steam can be represented as follows;

3Fe 4H₂O --------------> Fe₃O₄ + 4H₂

From the above reaction we can observe that the 4 moles of H₂O forms 4 Moles of Hydrogen gas.

Amount of water(Steam) given = 27 grams

Moles of H₂O = 27/18 = 1.5 moles.

Amount of H₂ produced by 1.5 moles of H₂O = 1.5 moles.

Mass of H₂O produced = 1.5 × 2 = 3 grams

Reaction between H₂ and N₂-

3H₂ + N₂ -----------> 2NH₃

3 moles of H₂ produces 2 moles of NH₃

1 mole of H₂ will produce 2/3 = 0.6 mole of NH₃

1.5moles of H₂ will produce 0.6 × 1.5 = 0.9 ≈ 1 mole Of NH₃.

we know that, 1 mole = Avogadro's Number

Number of molecules of NH₃ formed = Avogadro Number.

Hence, The correct answer is option (1) Avogadro Number.

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