Question

H20, is reduced rapidly by Sn2t to give H,O and Sn4! H20, is decomposed slowly at room temperature to yield O2 and H.O.
136 g of 10% by mass of H2O2 in water is treated with 100 mL of 3 M Sn2! and then the mixture is allowed to stand until no further
reaction occurs. The reaction involved are:
2H+H.0, + Sn2+ Sn!! + 2H2O
2H202 + 2H2O + O2
th eq of h2o2 left after react with sn is
​

Answer 1

Answer:

h2o means water so it will be sn + h2o

Explanation:

this is 2H+H.O,+SN2+SN

SO SN+H20