Question

What is the volume of 170 g Ammonia at STP

10 L
22.4 L
224 L​

Answer 1

$\bf\huge ANSWER$

Mass of ammonia = 170 g

Molecular mass of ammonia = 17 g

$\rm Number \ of \ moles = \dfrac{Mass \ of \ ammonia }{Gram \ molecular \ mass}$

                         $\rm = \dfrac {170}{17}$

                         $\rm = \bf 10$

1 mole of any gas occupies 22.4 L of volume .

Volume occupied by 170g of  Ammonia = 22.4 × 10 = 224 L

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