H2O+Br2 gives HBr+HOBr2 ?
In this reaction bromine acts as?
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In this reaction,
H2O+Br2 ----> HBr+HOBr2
On the reactant side the oxidation state of Br2 is 0
On the product side the oxidation state of Br in
HBr is -1 and in HOBr it is +1
Hence Br is oxidized as well as reduction of Br takes place this means it acts as both reducing as well as oxidizing agent (respectively)
It is a disproportionation reaction
I hope this helps ( ╹▽╹ )
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