H2S + SO2 -----> S + H2O
BALANCE THE EQUATION :
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BALANCE EQUATION
H2S + SO2 -----> H2O+ S
(Hydrogen sulfide + Sulfur dioxide)
In Following equation :-
In Reactant side ↪
H = 2
S = 3
O = 2
In Product Side ↪
H =2
O = 1
S= 1
Therefore :-
SO2 + H2S -----> S + 2H2O
⇒ On the LHS the number of molecules of H2S should be twice the number of molecules of SO2.
So, as an intermediate step, we tentatively put SO2+2H2S=S+H2O.
↪We should have two molecules of water on the RHS.
So, we modify the equation to
▶SO2+2H2S=S+2H2O
Now there are three sulphur atoms on the LHS.
⇒ There should be three sulphur atoms on the RHS also.
So we get the balanced equation
↪SO2+2H2S=3S+2H2O.
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