H₂S₂O₇(l) + H₂O(l) → H₂SO₄(1) , Balance the equation stepwise
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Answer ⇒ H₂S₂O₇(l) + H₂O(l) → 2H₂SO₄
Explanation ⇒
The reaction given above is of the Perpetration of the Sulphuric Acid by the contact process.
The given reaction is the last reaction of the Contact process.
During the Process, First Sulphur was oxidized to the Sulphur dioxide and then Sulphur dioxide is converted into the Sulphur trioxide at the temperature of 450° C to 500° C in the Presence of the Vanadium oxide at 1 atm Pressure.
S + O₂ ----------→ SO₂
2SO₂ + O₂ ---------→ 2SO₃
Now, this SO₃ prepared made to react with the Sulphuric acid to form the Oleum (or H₂S₂O₇) or Pyrosulphuric Acid.
SO₃ + H₂SO₄ ----------→ H₂S₂O₇
Now, this Pyrosulphuric acid or Oleum is reacts with the water to form the 98% concentrated Sulphuric Acid.
______________________________
H₂S₂O₇ + H₂O ----------→ 2H₂SO₄
______________________________
Hope it helps.
Answer ⇒ H₂S₂O₇(l) + H₂O(l) → 2H₂SO₄
Explanation ⇒
The reaction given above is of the Perpetration of the Sulphuric Acid by the contact process.
The given reaction is the last reaction of the Contact process.
During the Process, First Sulphur was oxidized to the Sulphur dioxide and then Sulphur dioxide is converted into the Sulphur trioxide at the temperature of 450° C to 500° C in the Presence of the Vanadium oxide at 1 atm Pressure.
S + O₂ ----------→ SO₂
2SO₂ + O₂ ---------→ 2SO₃
Now, this SO₃ prepared made to react with the Sulphuric acid to form the Oleum (or H₂S₂O₇) or Pyrosulphuric Acid.
SO₃ + H₂SO₄ ----------→ H₂S₂O₇
Now, this Pyrosulphuric acid or Oleum is reacts with the water to form the 98% concentrated Sulphuric Acid.
______________________________
H₂S₂O₇ + H₂O ----------→ 2H₂SO₄
______________________________
Hope it helps.
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