Chemistry, asked by Anonymous, 5 months ago

Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximately 67200 g. The number of iron atom ( at. weight of Fe is 56) present in one molecule of haemoglobin are
(a) 1
(b) 6
(c) 4
(d) 2
Answer in step wise​

Answers

Answered by ADARSHBrainly
21

(c) 4

\huge \huge\bold\color{blue}{\underbrace{\overbrace{\mathfrak{\color{red}{✍Answer⭐}}}}}

Given:-

  • Haemoglobin contains 0.33% of iron by weight.
  • molecular weight of haemoglobin is approximately 67200 g.
  • weight of Fe is 56

To find :-

  • The number of iron atom present in one molecule of haemoglobin are= ?

Let:-

  • number of iron atoms in one molecular of haemoglobin =x
  • 0.33 g of Fe is present in haemoglobin = 100 g

56x g of Fe is present in haemoglobin are

 \\   \mathtt{ =  \frac{100 \times 56x}{0.33} g}

 \\  \mathtt{ \therefore \frac{100 \times 56x}{0.33} = 67200 }

 \mathtt{ \implies{{100 \times 56x = 67200 \times 0.33}}}

 \mathtt{ \implies100 \times 56x = 22176}

 \\  \mathtt{ \implies56x =  \frac{22176}{100} }

 \mathtt{ \implies56x = 221.76}

 \\  \mathtt{ \implies x = \frac{221.76}{56} }

 \color{green}{\boxed {\mathtt{\implies  x = 3.96 \boxed{ ≈4}}}}

The number of iron atom present in one molecule of haemoglobin are 4.

Answered by Anonymous
2

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