Question

Haemoglobin has 0.25% by mass of Iron (Fe) and cytochrome protein has 0.28% by mass of Iron
(Fe). If a molecule of haemoglobin contains 4 atoms of iron and a molecule of cytochrome protein
contains 1 atom of iron, then the ratio of molecular mass of haemoglobin and cytochrome protein is:
[Atomic mass: Fe = 50]
(A) 1.12
(B) 2.24
(C) 4.48
(D) 8.96​

Answer 1

Option d. 8.96 ...

Thanks

Answer 2

Answer:

A] 1.12

Explanation:

• 0.25% means

 100 gm of haemoglobin contains 0.25 gm of Fe

therefore,

1 gm of  haemoglobin will contain = 0.25/100 = 25*10⁴ gm of Fe

Molecular mass = Atomic mass/mass of Fe per gram

Molecular mass = 50/25*10⁴ -----------[1]

• 0.28% means

100 gm of cytochrome protein contains 0.28 gm of Fe

therefore,

1 gm of cytochrome protein  will contain = 0.28/100 = 28*10⁴ gm of Fe

Molecular mass = Atomic mass/mass of Fe per gram

Molecular mass = 50/28*10⁴---------[2]

• The ratio of molecular mass of haemoglobin and cytochrome protein

                                [1]/[2]

                                   [50/25*10⁴]/ [50/28*10⁴]

                                    28/25

                                   = 1.12

#SPJ3