HALA EVERYONE,
HERE IS THE QUESTION!!!
If 3 cot theta=2 find the value of 2 sin theta - 3 cos theta divided by 2 sin theta + 3 cos theta
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Step-by-step explanation:
3 cot theta = 2
=>3 cos theta / sin theta = 2
=>3 cos theta = 2 sin theta-------(i)
so,
2 sin theta - 3 cos theta / 2 sin theta + 3 cos theta
=2 sin theta - 2 sin theta / 2 sin theta + 2 sin theta------(from (i))
= 0/ 4 sin theta
=0
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