Question

half life is 3824 of radioactive how many days it will to be reduce 76%

Answer 1

Half life period =0.693/k

24.1=0.693/k

k=0.693/24.1

k=0.028755

All Radioactive decays follow first order kinetics

kt=2.303*log(100/10)

kt=2.303

t= 2.303/k

t=2.303/0.028755

t=80 days

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plz Mark brillante