Half life of 24na is 900 minutes.whats it's decay constant
Answers
Answered by
10
Dear Student,
◆ Answer -
Radioactive decay constant of 24Na = 1299 /min
● Explanation -
# Given -
t½ = 900 min
# Solution -
For a radioactive substance, half life and radioactive decay constant are related as -
t½ = ln2 / k
k = t½ / ln2
k = 900 / 0.693
k = 1299 /min
Hence, radioactive decay constant of 24Na is 1299 /min.
Thanks dear. Hope this helps you...
Similar questions