Chemistry, asked by Fadufari737, 10 months ago

Half life of 35s is 87.8 d what percentage of 35s sample remains after 180 d ?​

Answers

Answered by chemisst
0

Answer:

25%

Explanation:

Given data:

Half life of S-35 = 87.8 days

Percentage of sample after 180 days = ?

Solution:

Number of half lives = T elapsed / half life

Number of half lives = 180 days / 87.8 days

Number of half lives =  2

At time zero = 100%

At first half life = 100%/2 = 50%

At second half life = 50%/2 = 25%

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