Half of a herd of deer are grazing in field and three fourth of the remaining are playing nearby.the rest 9 are drinking water from pool .find the number of deer in herd
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Let the Total no. of deer be x
x/2 + 1/2(3x/4) + 9 = x
3/8x + 1/2x + 9 = x
3/8 + 1 × 4/8x + 9 = x
(3 + 4)x/8 + 9 = x
Transposing x to the other side so it will be -x and transposing 9 to the other side so it will be -9
7x/8 - 8x/8 = -9
-x/8 = -9
Transpose /8 to the other side so it will become ×8
-x = -9 × 8
-x = -72
x = 72 (Because both minus signs killed each other or it got cancelled)
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x/2 + 1/2(3x/4) + 9 = x
3/8x + 1/2x + 9 = x
3/8 + 1 × 4/8x + 9 = x
(3 + 4)x/8 + 9 = x
Transposing x to the other side so it will be -x and transposing 9 to the other side so it will be -9
7x/8 - 8x/8 = -9
-x/8 = -9
Transpose /8 to the other side so it will become ×8
-x = -9 × 8
-x = -72
x = 72 (Because both minus signs killed each other or it got cancelled)
Hope it Helps YOU ✌. Pls Mark me the Brainliest.
Answered by
0
Answer:
the number of deers in the herd are 72
Step-by-step explanation:
let the number of deers in the herd = X
no. of deers grazing in the field = X/2
no. of deers playing nearby = 3/4 of X/2
= (3/4)(X/2)
= 3 X / 8
no. of deers drinking water from nearby pond = 9
according to the question,
9 + X/2 + 3 X / 8 = X
9 + 4 X/8 +3 X/8 = X
9 + 7 X/8 = X
9 = X - 7 X/8
9 = 8 X/8 - 7 X/8
9 = X/8
X = 8×9
X = 72
total number of sheeps = 72
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