Question

Half of a herd of deer are grazing in the field and three fourths of the remaining are playing nearby . The rest 9 are drinking water from the pond. Find the number of deer in the herd .

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Answer 1

$\huge \red{\boxed{\fcolorbox{blue}{orange}{\bf \color{lime}{72 deers}}}}$

Step-by-step explanation:

QUESTION :-

Half of a herd of deer are grazing in the field and three fourths of remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.

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SOLUTION :-

Let the number of total deers as x

then,

• Half of herd's deer are grazing = $\dfrac{x}{2}$

• Three fourths of remaining are playing nearby = $\frac{x}{2} \times \frac{3}{4} = \dfrac{3x}{8}$

• Rest 9 are drinking water.

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So,

Sum of all deers = total number of deers in herd

$\bf = > \frac{x}{2} + \frac{3x}{8} + 9 = x \\ \\ \bf = > \frac{4x + 3x + 72}{8} = x \\ \\ \bf = > 7x + 72 = 8x \\ \\ \bf = > 72 = 8x - 7x \\ \\ \bf = > 72 = x \\ \\ \bf = > \large \bf \red{x = 72}$

Hence,

There are total 72 deers in the herd.

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Hope it helps.

#BeBrainly :-)

Answer 2

Answer :-

Answer :- The total number of deer = 72

Step - by - step explanation :-

Let the total number of deer be x.

Deer grazing in the field = x/2

Deer playing nearby = x/2 × ¾ = 3x/8

Deer drinking water = 9

• According to the given details, the equation becomes

x/2 + 3x/8 + 9 = x

(4x + 3x)/8 + 9 = x

• Rearranging the equation and combining like terms we get

⇒ 7x/8 + 9 = x

⇒ x – 7x/8 = 9

⇒ (8x – 7x)/8 = 9

⇒ x = 9 × 8

⇒ x = 72