Half of the sum of two numbers is equal to 42 one third of the difference is equal to 4 find the two number
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Step-by-step explanation:
let the numbers be 'a' and 'b' respectively
according to the question,
(a+b) /2 = 42
a+b = 42*2
a+b = 84 ....(i)
(a-b) /3 = 4
a-b = 4*3
a-b = 12 ....(ii)
subtract (ii) from (i)
a+b-(a-b) = 84-12
a+b-a+b = 72
b+b = 72
2b = 72
b = 72/2
∴b = 36
now, put the value of 'b' in (i)
a+36 = 84
a = 84-36
∴a = 48
∴the two numbers are 48 and 36
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Answer is 36 and 48.Please mark me as Brainliest.
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