Question

Half the perimeter of a rectangular garden whose length is 4 m more than its width is 36m. find the dimensions of the garden ​

Answer 1

Answer:

Step-by-step explanation:

p=2*36=72 m

breadth=b

length=b+4

p=2(l+b)

72/2=b+4+b

36=2b+4

2b=36-4

2b=32

b=32/2

b=16 m

l=16+4=20 m

Answer 2

Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

Let length of rectangle = x m

With of the rectangle = y m

Given that whose length is 4 m more than its width

so that

x = 4 + y

plug y = -18 , 0, and 18 we get

x = 4 - 18 = -14

x = 4 +0 = 0

x = 4 + 18 = 22

X

-14

0

22

y

-18

0

18

Given that Half of the perimeter of the rectangle is 36 m so

Formula of perimeter of the rectangle = 2(x+y)

Half of perimeter of rectangle = (1/2)*2(x + y) = x + y

So our equation will

x + y = 36

Subtract y both side we get

X = 36 – y

Plug y = 36 ,18 and 0 we get

X = 36 – 36 = 0

X = 36 – 18 = 18

X = 36 – 36 = 0

X

0

18

36

y

36

18

0

Hence length of garden = 20 m

Width of garden = 16 m