Half the perimeter of a rectangular garden whose length is 4 m more than its width is 36 m. Find the dimension of the garden
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Answered by
19
Half the perimter of rectangular garden is 36 so, 2(l+b)/2=36
i.e. (l+b)=36
Lenth is 4 m more than its width solet width x and lenth be x+4
Put this in eq above x+x+4=36
2x+4=36
2x=32
x=16
i.e. (l+b)=36
Lenth is 4 m more than its width solet width x and lenth be x+4
Put this in eq above x+x+4=36
2x+4=36
2x=32
x=16
Answered by
21
Answer:
It is given that, half of the Perimeter of reactangular garden is 36 :]
So,
➦ 2(l + b)/2 = 36
➦ l + b = 36.......[Equation (i)]
Now,
Let width be x
and length be x + 4
Putting this values in equation (i) we get,
➝ l + b = 36
➝ x + x + 4 = 36
➝ 2x + 4 = 36
➝ 2x = 36 - 4
➝ 2x = 32
➝ x = 32/2
➝ x = 16 m
Therefore,
Width of reactangular garden = x = 16 m
Length of the reactangular garden = x + 4 = 16 + 4 = 20 m
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