Question

Half the perimeter of a rectangular garden, whose length is 4 m more than its width is 36 m. Find the dimensions of the garden graphically.


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Answer 1

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

Answer 2

Given :-

• Perimeter of a rectangular garden = 36m
• Let the width be x
• Length = x + 4m

We know that :-

• Perimeter of a rectangle = 2 (length + Breadth)

Solution :-

Putting the values we get,

$= > 2(x + x + 4) = 36m\\ = > 2 \times 2x + 8 = 36m \: \: \\ = > 4x + 8 = 36m \: \: \: \: \: \: \: \: \: \\ = > 4x = 36m - 8 \: \: \: \: \: \: \: \: \: \\ = > x = \frac{28m}{4} = 7m \: \: \: \: \:$

Therefore,

Length = x + 4 = 7 + 4 = 11m

Width = x = 7m

Verification :-

Putting the values of length and width,

$= > 2(7 + 11)m \\ = >( 2 \times 18)m \\ = > 36m \: \: \: \: \: \: \: \:$

Hence verified.

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