Question

Half the perimeter of rectangle garden , whose length is 4 m more than its width,is 36 m . find the dimensions of the garden.

Answer 1

Answer:

length of a garden is 20 metres

Step-by-step explanation:

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

Answer 2

Answer:

Length = 20m and Width = 16m

Step-by-step explanation:

As we are given a rectangular garden, assuming 'l' to be it's length and 'w' be it's width;

Now as we are given that the length of the garden is 4m more than it's width; that means;

l = w + 4 --(i)

Also we are given that half of the perimeter is 36m, and we know that perimeter is summation of all the sides of any geometrical object; thus, letting 'p' as the perimeter; therefore, perimeter of rectangle would be;

p = l+l+w+w

p = 2l+2w

p = 2(l+w)

Or;

p/2 = l+w

Now, 'p/2' is half of the perimeter, which is '36m' as given, then;

36 = l+w --(ii)

And we know that;

eq(i) => l = 4 + w

Then, put the value of 'l' from eq(i) in eq(ii):

36 = 4+w+w

32 = 2w

Or;

w = 16m

And eq(i)=>

l = 4+w

Put the value of 'w' in above equation;

l = 4+w

l = 4 + 16

l = 20m

Thus the dimensions of the garden are 16m and 20m