Question

Hammer of mass 400 grams moving at 3:30 metre per second strikes and air the nail stop the hammer in a very short time of 0.01 second what is the force

Answer 1

Answer:

Explanation:

m = 500g = 0.5 kg

v = 0 m/s

u = 50 m/s

t = 0.01 s

F = m(v-u) / t

F = 0.5 (50-0) / 0.01

F = 0.5 x 50 x 100 / 1

F = 2500 N

Force of nail = 2500 N

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Answer 2

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