Question

happens to the volume of the cylinder with radius r and height h, when its
(a) radius is halved (b) height is halved.​

Answer 1

Step-by-step explanation:

a)h is same

b)radius is same

Answer 2

Answer:

volume of cylinder=πr²h

in 1st case,

r' = r/2

volume of cylinder=

$\pi \: { (\frac{r}{2} )}^{2}h \\ \pi \: \frac{ {r}^{2} }{4} h \\ \: \frac{\pi \: {r}^{2}h }{4} = \frac{volume \: of \: cylinder}{4}$

in 1st case new volume of cylinder is become one-fourth of given volume

in 2nd case,

h'=h/2

volume of cylinder=

$\pi {r}^{2} \frac{h}{2} \\ \frac{\pi {r}^{2} h}{2} = \frac{volume \: of \: cylinder}{2}$

in 2nd case new volume of cylinder is become halve of given volume.

hope it helps you....