Question

HAPPY HOLI!!!!!
‘Two water taps together can fill a tank 9 and 3/8 hours. The tap of larger diameter takes 10 hour less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.’

Answer 1

Answer:

Happy Holi

Let the larger diameter tap fills the tank alone in (x – 10) hours.

In 1 hour, the smaller diameter tap can fill 1/x part of the tank.

In 1 hour, the larger diameter tap can fill 1/(x – 10) part of the tank.

Two water taps together can fill a tank in 75 / 8 hours.

But in 1 hour the taps fill 8/75 part of the tank.

1 / x + 1 / (x – 10) = 8 / 75.

( x – 10 + x ) / x ( x – 10) = 8 / 75.

2( x – 5) / ( x2 – 10 x) = 8 / 75.

4x2 – 40x = 75x – 375.

4x2 – 115x + 375 = 0

4x2 – 100x – 15x + 375 = 0

4x ( x – 25) – 15( x – 25) = 0

( 4x -15)( x – 25) = 0.

x = 25, 15/ 4.

But x = 15 / 4 then x – 10 = -25 /4 which is not possible since time

But x = 25 then x – 10 = 15.

Larger diameter of the tap can the tank 15 hours and smaller diameter of the tank can fill

the tank in 25 hours.

please brainlist

Answer 2

$<marquee> correct answer is 25 hours </ marquee>$

$\huge\boxed{\fcolorbox{cyan}{blue}{hare is your answer}}$