Question

Hari babu left one-third of his property to his son, one-fourth to his daughter the remainder to his wife. If his wife's share is ₹ 18000, what was the worth of total property.

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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• Let the total value of Hari Babu's property be 'x'.



• Then, his son's share -

= ⅓ of total property

= 1/3 × x

= x/3



• And, his daughter's share -

= ¼ of total property

= 1/4 × x

= x/4



• Now, remaining property (wife's share)

= x - [ (x/3) + (x/4) ]

= x - [4x + 3x]/12

= x - 7x/12

= (12x - 7x)/12

= 5x/12



• But, wife's share = 18000 Rs.

=> 5x/12 = 18000

=> x = 18000 × 12/5

=> x = 216000/5

=> x = 43200

Hence, Total Value of Hari Babu's property = 43,200 Rs.

$<marquee>Therefore, your answer is 43200 Rs.</marquee>$
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Thank you.. ;-)

Answer 2

Step-by-step explanation:

x/3+x/4+18000

4x+3x+216000=12x

7x+216000=-21600

-5x=21600

x=43000

Hari babu total worth is 43000