Math, asked by ggghh3187, 1 year ago

Hari babu left one-third of his property to his son, one-fourth to his daughter the remainder to his wife. If his wife's share is â‚ą 18000, what was the worth of total property.

Answers

Answered by tejasgupta
14

Heya !!

\text{Let the total property be Rs. x}\\\\\text{Son's share = $\dfrac{1}{3} x$}\\\\\text{Daughter's share = $\dfrac{1}{4} x$}\\\\\text{Wife's share = Remaining Property = $x - \dfrac{1}{3} x - \dfrac{1}{4} x$}\\\\= \dfrac{12x - 4x - 3x}{12}\\\\= \dfrac{5}{12} x\\\\\text{But, Wife's share = Rs.18,000}\\\\\therefore, \dfrac{5}{12} x = 18000\\\\\implies x = 18000 \times \dfrac{12}{5} = \lage \underline{\boxed{\boxed{Rs. \: 43,200}}} - \text{Total property that the man left.}

Hope it helps !!

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