Math, asked by saurav178, 1 year ago

Hari is twice as old as his son 20 years ago he was four times as old as his son find the present age of each

Answers

Answered by BrainlyQueen01
54
HEY MATE!

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Explanation:-

let the age of hari's son be x.

and, the age of hari be 2x.

given: 20 years ago ..

age of hari's son = (x-20)

age of hari = 4(x-20)

now,

(2x-20) = 4(x-20)

2x-20 = 4x-80

2x-4x = -80+20

-2x = -60

(minus- minus cancelled).

2x=60

x= 60/2

x= 30.

so, the son's present age is 30 years

and , the hari's present age is 2×30=60 years.
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preetdhami: good
BrainlyQueen01: thnx
alson61: very easy
Answered by User8ba24
67
Thanks for the asking questions

in this case we need to be let
the age of hari's son be x.
and, the age of hari be 2x.

given that - 20 years ago age of hari's son = (x-20) and age of hari = 4(x-20)

Then

(2x-20) = 4(x-20)

2x-4x = -80+20

-2x = -60

x= 60/2

x= 30.

so, the son's present age is 30

and , the hari's present age is =60

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