Question

haris is 40 years old and roshan is 60 years old. how many years ago was the ratio of their ages 3:5?​

Answer 1

Answer:

$\large \underline{\boxed{\mathsf{10yrs \: ago}}}$

Step-by-step explanation:

Given :

Haris is 40 years old and roshan is 60 years old.

To Find :

How many years ago was their ages in 3:5 ratio.

Solution :

Now let the

No: of years ago in which there ages was in ratio 3:5 be X

Therefore,

• Harish's age X years ago = 40 - x

and

• Roshan's age X years ago = 60 - x

According To Question

X years ago their ages was in ratio 3:5 that is

$\mathsf{\dfrac{Harish's \: age \: x \: years \: ago}{Roshan's \: age \: x \: years \: ago} = \dfrac{3}{5}}$

That is -

$\implies \mathsf{ \dfrac{40 - x}{60 - x} = \dfrac{3}{5}}$

By Cross Multiplication

$\implies \mathsf{5(40- x) = 3(60 - x)}$

$\implies \mathsf{200 - 5x = 180 - 3x}$

$\implies \mathsf{2x = 20}$

Therefore,

$\implies \mathsf{x = \dfrac{20}{2} = 10yrs}$

Thus Required answer Is

$\underline{\boxed{\mathsf{10yrs \: ago}}}$

Answer 2

Answer:

Step-by-step explanation:

Given :-

Haris is 40 years old and roshan is 60 years old.

To Find :-

Years ago was the ratio of their ages 3:5

Solution :-

Let the ratio was 3 : 5, x years ago.

According to the Question,

⇒ 40 - x/60 - x = 3/5

⇒ 5(40 - x )= 3(60 - x)

⇒ 200 - 5x = 180 - 3x

⇒ 2x = 20

⇒ x = 20/2

⇒ x = 10

Hence, 10 years ago was the ratio of their ages 3:5.