Question

Harish walks a certain distance on Monday. He
increases the distance by 500 m every day for the
rest of the week. If the total distance he walked
during the week is 14 km, find the distance he
walked on Wednesday,​

Answer 1

Answer:

the given problem pertains to arithmetic progression.

given d = 500m and S7 = 14000 m, n = 7

to find a3

let us find the distance he covered Monday.

a = ?

Sn = n/2 [ 2a + (n-1)d ]

14000 = 7/2 [ 2a + (7-1) 500 ]

14000 = 7/2 [ 2a + 3000 ]

14000 = 14a/2 + 10500 ]

14000 - 10500 = 14a/2

3500 = 14a/2

7000 = 14 a

therefore a = 7000/14

= 500

he walked 500 m on first day

now the distance he walked on Wednesday

a3 = a + (n-1)d

= 500 + 2×500

= 500 +1000

= 1500 m

Answer 2

Answer:

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