Harry Potter is sitting 2.0 meter from the center of a merry-go-round when Draco Malfoy casts a spell that glues Harry in place and makes the merry-go-round start spinning on its axis. Harry has a mass of 50.0 kg and can withstand 5.0 g's of acceleration before passing out. What is the magnitude of Harry's angular momentum when he passes out?
ItzPiya:
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Answers
Answered by
10
Explanation:
Distance of harry potter(s) = 2 m
mass of harry potter (m) = 50 kg
acceleration he can withstand (s) = 5 m/s
Your question is what is his angular momentum (L) =???
Formula
L = mvr
here is radius = distance from centre
r = 2 m
m = 50 kg
v = 5 g { I noticed that 1 g = 9.8 m/s^2}
v = 49 ms^-2
substitute the given values
L = 50 * 49 *2
= 100 * 49
= 4900 kg m2 s−1
His magnitude is positive
Harry's angular momentum of 4900 kg m2 s−1 when he passes out
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True potterhead
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Answered by
5
Answer:
Literally,Harry Potter?!
ok fine, here's your Answer
Assuming that the spell is a force then rF = I alpha. And using alpha = a/r, we using the max acceleration of 5g that 5mgr = Ia/r However I'm not sure where to go from this, how do i get v, sorry about that!
T=I alpha L=mvr.
hope this helps you!
and literally,u have a MATHS chapter/Question on Harry Potter? that's weird...(atleast a little)
and thanks for your reply.
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Have a lovely day Ahead!❣️
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