Question

harsh is 40 yrs lod and ritu is 60 yrs old.how many yrs ago was the ratio of their ages 3:5.

Answer 1

let this was x years ago.
before x years,
$\frac{40 - x}{60 - x} = \frac{3}{5}$
on solving by cross multiplication, we get
$x = 10 \:$
so the answer is 10 years.

Answer 2

Solution:

________✍

$Harsh \ is \ 40 \ years\\ Ritu \ is \ 60 \ years\\\\ Let \ x \ years \ before \ their \age \ ratio \ was\ 3 : 5\\\\ So' \ x\ years \ ago \ \\ Harsh = 40 - x\\ Ritu = 60 - x\\\\ ACQ.\\\\\ \frac{40 - x}{60 - x} = \frac{3}{5} \\\\ 200 - 5x= 180 - 3x\\\\ -5x +3x= 180 -200\\\\ -2x = -20\\\\ x = \frac{-20}{-2} \\\\ x = 10\\\\ Hence , \ 10 \ years \ before \ their \ age \ ratio \ was \ 3:5$

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