has written.
Both of Lalima and Romen clean their garden. If Lalima works for 4 days and Romen
works for 3 days, then part of the work is completed. Again, if Lalima works for 3 days
and Romen works for 6 days, then part of the work is completed. Let us form the
Simultaneous equations and write the number of days required to complete the work
separately by Lalima and Romen by calculating the solution.
Answers
Given :
To complete a part of work
The number of days did Lalima worked = 4
The number of days did Romen worked = 3
Again
To complete a part of work
The number of days did Lalima worked = 3
The number of days did Romen worked = 6
To Find :
The number of days did Lalima worked alone = x days
The number of days did Romen worked alone = y days
Solution :
Lalima's 1 day work =
So, Lalima's 4 day work = × 4 =
Romen's 1 day work =
So, Romen's 3 day work = × 3 =
∴ 1 day work for Lalima and Romen = + = 1
or, + = 1
or, 4 y + 3 x = x y ...........1
Again
Lalima's 3 day work = × 3 =
Romen's 6 day work = × 6 =
∴ 1 day work for Lalima and Romen working together = + = 1
or, + = 1 = 1
or, 3 y + 6 x = x y ...........2
Solving eq 1 and 2
2 ( 4 y + 3 x ) - ( 3 y + 6 x ) = 2 × x y - x y
Or, ( 8 y - 3 y ) + ( 6 x - 6 x ) = x y
Or, 5 y + 0 = x y
∴ x = 5
So, Number of days did Lalima work alone is 5 days
Put The value of x into eq 2
3 y + 6 x = x y
Or, 3 y + 6 × 5 = 5 y
Or, 5 y - 3 y = 30
Or, 2 y = 30
∴ y =
i.e y = 15 days
So, Number of days did Romen work alone is 15 days
Hence,.
Number of days did Lalima work alone is 5 days
Number of days did Romen work alone is 15 days
Answer
no.of day lalima work 5 days
no.of day Roman work 15 days