Hasan buys two kinds of cloth material for school uniform,shirt material that cost him ₹50 per meter and trouser material that cost him ₹90 per meter,For every 2 meter of the trouser material,he buys 3 meter of the shirt material. He Sells the materials at 12% and 10% profit respectively.His total sale is ₹36,660. How much trouser material did he buy?
Answers
Step-by-step explanation:
Solution
Let the trouser material bought by him be = 2x
Let the shirt material be bought by him be = 3x
Selling price of shirt material per meter = ₹ 50 + 50 × (12/100) = ₹ 56
Selling price of trouser material per meter = ₹ 90 + 90 × (10/100) = ₹ 99
Total amount of sale = ₹36,600
According to the given details, the equation becomes
(2x × 99) + (3x × 56) = 36600
⇒ 198x + 168x = 36600
⇒ 366x = 36600
⇒ x = 36600/366
⇒ x = 100
Total trouser material he bought = 2x = 2 × 100 = 200 m.
The shirt material brought by him = 3x= 3 x 100 = 300 m
Answer
Total trouser material he bought = 2x = 2 × 100 = 200 m.
Answer:
200m
Step-by-step explanation:
Let material bought for trousers and shirts be 2x meters and 3x meters respectively.
Cost price of 2x metres of trouser material at Rs. 90 per metre =Rs(90×2x)=Rs180x and
Cost price of 3x metres of shirt material at Rs. 50 per metre =Rs(50×3x)=Rs150x
Given, profit in case of shirt material = 12%
∴ Its S.P. =Rs(150×
100
112
)=Rs168x
Also, profit in case of trouser material = 10%
∴ Its S.P. =Rs(180×
100
110
)=198x
∴ Total selling price =Rs.(168x+198x)
=Rs.366x
But the total selling price is given as Rs. 36600.
∴366x=36600⇒x=
3666
36660
=100
Thus, the trouser material purchased
=2×100m
=200m