Question

Having freckles (F) is dominant over not having freckles (f). A parent with freckles is crossed with a parent without freckles. The Punnett square shows the possible genotypes of the offspring.

What is the probability that an offspring will have a homozygous dominant genotype?
%

What is the probability that an offspring will have a heterozygous genotype?
%

What is the probability that an offspring will have a homozygous recessive genotype?
%

Answer 1

Answer:

Explanation:

The problem in this question is knowing the genotype of the parent with freckles because they can be Homozygous FF or Heterozygous Ff.

The parent with freckles will be ff

If the parent is FF

Then - zero chance of homozygous dominant

100% heterozygous genotype (all are Ff)

Zero that they will be homozygous recessive

If parent is Ff

Then - zero chance of homozygous dominant

50% heterozygous genotype (all are Ff)

50% that they will be homozygous recessive (ff)

Answer 2

AnswI did it on edguinity. The answer is in the photo.

Explanation: