Question

hay = please help me
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An open wooden box 80cm long.65cm wide and 45cm high is made of 2.5cm thick wood.
find (i) the capacity of the box,
(ii) volume of wood used and (iii) weight of the box,it begin given that 100cm³ of the wood weight 8g

if you dont know dont give me answer

oll the best

Answer 1

hay!!

solution- __________________________________

Extrnal length of box = 80cm
External breadth of the box =65cm
External heght of the box = 45cm
External volume of the box =

(80×65×45)cu cm = 234000cm³

Internal length of the box =>>

[80-(2.5×2)]cm=> (80-5) cm => 75cm

Internal breath of the box =>

[65-(2.5×2)]cm => (65-5) =60cm

Interna hight of the box =

(45-2.5)cm = 42.5cm

1. capacity of the box = internal volume of the box
= (75×60×42.5)cm³= 191250cm³

2. Volume of the wood used =
(external volume )-(internal volume )
= (234000-191250)cm³= 42750cm³

3. weight of 100cm³ of the wood =8g

weight of 42750cm³ of the wood
= (8/100 ×42750)g
= 3420g

= 3kg 420g.

Answer 2

Outer dimension of box = 80 * 65 * 45

Thickness of wood : - 2.5cm


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= > internal dimensions of box
= (80−2.5×2)×(65−2.5×2)×(45−2.5)
= 75cm×60cm×42.5cm



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Therefore , capacity of the box = 75cm×60cm×42.5cm =191250cm^3
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outer volume of box = 80cm×65cm×45cm = 234000cm^3


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Therefore, volume of wood used
= 234000cm^3−191250cm^3 = 42750cm^3




Therefore, weight of box = 8 / 100 *42750

= >
3420 gram ( 3 kg 420 g )