Question

HBr reacts with CH₂ = CH – OCH₃ under anhydrous
conditions at room temperature to give
(a) BrCH₂ – CH₂ – OCH₃ (b) H₃C – CHBr – OCH₃
(c) CH₃CHO and CH₃Br (d) BrCH₂CHO and CH₃OH

Answer 1

Explanation:

I think the correct answer is (a)

Answer 2

HBr reacts with CH₂=CH-OCH₃ under anhydrous conditions at room temperature to give (a) BrCH₂-CH₂-OCH₃.

• HBr react with any alkene to form alkyl halide or haloalkane.
• When HBr reacts with an alkene under anhydrous condition at room temperature it follow Antimarkovnikov rule.
• According to antimarkovnikov rule the halogen of HBr will react and bind on the carbon having more number of protons i.e, Hydrogen and the hydrogen will be react and bond with the carbon having less number of proton.