HBr reacts with CH₂= CH – OCH₃ under anhydrous conditions at room temperature to give
(a) BrCH₂ – CH₂ – OCH₃
(b) H₃C – CHBr – OCH₃
(c) CH₃CHO and CH₃Br
(d) BrCH₂CHO and CH₃OH
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i think BrCH₂CHO and CH₃OH
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