Question

HCF (16,y)=8 and LCM (16,y)=48, find y

Answer 1

Two numbers are = 16,y

As we know that

HCF × LCM = PRODUCT OF NUMBERS

HCF= 8,LCM = 48

8×48 = 16× y
y= 24

Answer 2

If lcm(a,b)=l, hcf(a,b)=h
a*b=l*h
16*y=48×8
y=(48×8)/16
y=3×8
y=24