Question

HCF 42,54,64
find the sum of HCF ​

Answer 1

42=

2 21

3 7

7 7

7 1

42=2X3 x 7 x 7

54=

2 27

3 9

3 3

3 1

54 = 2 x 3 x 3 x 3

64=

2 32

2 16

2 8

2 4

2 2

2 1

64 = 2 x 2 x 2 x 2 x 2 x 2

the HCF of all is 2

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Answer 2

Given: The numbers are$42,54,\ and\ 64$.

We have to find the HCF of the above numbers.

As we know that the greatest common divisor(HCF) of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are$42,54,\ and\ 64$.

First, we will find the factors of the above numbers.

The factors of $42$ are: $1, 2, 3, 6, 7, 14, 21, 42$

The factors of $54$ are: $1, 2, 3, 6, 9, 18, 27, 54$

The factors of $64$ are: $1, 2, 4, 8, 16, 32, 64$

From the above, we can see that$2$ divides each of the given numbers.

Then the greatest common factor is$2$.

Hence, the HCF of the given numbers is$2$.